7.21开发测试面经
sql语句
表结构
表名:student
字段:id name score问题:成绩倒数第二/正数第二的学生名字
SELECT student.name, student.scores FROM student ORDER BY scores DESC LIMIT 1, 1
SELECT student.name, student.scores FROM student ORDER BY scores ASC LIMIT 1, 1
内外连接
SELECT student.name, student.scores, class.id FROM student INNER JOIN class ON student.
classid
= class.idSELECT student.name, student.scores, class.id FROM student LEFT JOIN class ON student.
classid
= class.id
SELECT student.name, student.scores, class.id FROM student RIGHT JOIN class ON student.
classid
= class.idselenium定位元素
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8driver.find_element_by_xpath()
driver.find_element_by_name()
driver.find_element_by_tag_name()
driver.find_element_by_link_text()
driver.find_element_by_partial_link_text()
driver.find_element_by_class_name()
driver.find_element_by_css_selector()
driver.find_element_by_id()tcp三次握手?握手的时候怎么确认对方的身份?
TCP四次挥手
网络七层模型及各层常见协议
算法
两数之和
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10class Solution(object):
def twoSum(self, nums, target):
hashtable = dict()
for i,num in enumerate(nums):
if target - num in hashtable:
return [hashtable[target-num], i]
hashtable[nums[i]] = i
return []实现LRU
LRU